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Which equation is perpendicular to the line 3x+y=10 and passes through the point(6,-5)?
4 months ago
Q:
Which equation is perpendicular to the line 3x+y=10 and passes through the point(6,-5)?
Accepted Solution
A:
A perpendicular line's slope is the opposite of a parallel line's slope, so it would be 1/3.
1/3 times 6 is two, and subtract 7 to get -5.
Therefore, -7 is the y-intercept.
So, the equation would be y=1/3x-7, so the answer is D.