Which equation has the components of 0 = x2 – 9x – 20 inserted into the quadratic formula correctly?

Answer:The required equation is [tex]x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}[/tex].Step-by-step explanation:If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then the quadratic formula is[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]The given quadratic equation is[tex]x^2-9x-20=0[/tex]Here, a=1, b=-9 and c=-20.Substitute a=1, b=-9 and c=-20 in the above quadratic formula.[tex]x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}[/tex]Therefore the required equation is [tex]x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}[/tex].