Which equation finds the value of x in the triangle below?
Accepted Solution
A:
we have that 1)
cot 70=x/12
Cot
70=[opposite side]/[adyacent side]=x/12
The
option 1 is correct
2)
cot 70=12/x
Cot
70=[opposite side]/[adyacent side]=x/12
The
option 2 is not correct
3)sec 20=x/12
Sec 20
=1/cos20
Cos
20==[opposite side]/[hypotenuse]=12/z
1/(1/cos20)------->
1/(12/z)------> z/12
The
option 3 is not correct
4) sec 20=12/x
Sec
20 =1/cos20
Cos
20==[opposite side]/[hypotenuse]=12/z
1/(1/cos20)------->
1/(12/z)------> z/12
The
option 4 is not correct the correct value is 1) cot 70=x/12