What is the sum of the polynomials (7x^3-4x^2)+(2x^3-4x^2)
Accepted Solution
A:
Your answer is... The problem to solve is:
(7x^3-4x^2)+(2x^3-4x^2)
Multiply the exponent of x by 3giving
The answer is x3
x^3 evaluates to x3
Multiply
x3 and 7
Multiply
x3 and 1
The x3
just gets copied along.
The answer is x3 x3
7*x^3 evaluates to 7x3
Multiply the exponent of x by 2giving 2x
The answer is 2x
x^2 evaluates to 2x
Multiply
2x and 4
Multiply
and 1
The
2x just gets copied along.
The answer is 2x
4*x^2 evaluates to
7*x^3-4*x^2 evaluates to4x2
Multiply the exponent of x by 3giving
The answer is
x^3 evaluates to 7x3 -4x2
Multiply x3 and 2
Multiply
x3 and 1
The
x3 just gets copied along.
The answer is x3 x3
2*x^3 evaluates to2x3
Multiply the exponent of x by 2giving
The answer is x2
x^2 evaluates to 2x3
Multiply x2
and 4
Multiply x2
and 1
The
x2 just gets copied along.
The answer is x2 x2
4*x^2 evaluates to 4x2
2*x^3-4*x^2 evaluates to2x3 -4x2
To add the polynomials
7x3 -4x2 and
2x3 -4x2 we try to add or combine terms in one polynomialwith any like terms in the other polynomial.
7x3+2x3
=9x3
-4x2+-4x2
=-8x2
The answer is 9x3 -8 2
(7*x^3-4*x^2)+(2*x^3-4*x^2) evaluates to9x3 -8x2
||||||The final answer is 9x3 -8 2||||||| Hope this helps!:) Took m FOREVER but I got it done! @SamSamySamantha