What is the completely factored form of x4 + 8x2 – 9?A(x + 1)(x – 1)(x + 3)(x + 3)B(x + 1)(x - 1)(x2 + 9)C(x2 – 1)(x + 3)(x – 3)D(x + 1)(x + 1)(x + 3)(x + 3)

The answer is B:
[tex] {x}^{4} + 8 {x}^{2} - 9[/tex]
[tex] = ( {x}^{2} + 9)( {x}^{2} - 1)[/tex]
[tex] = (x + 1)(x - 1)( {x}^{2} + 9)[/tex]
Hope this helped