What equation can be used to find the length of AC(10)sin(40°)=AC(10)cos(40°)=AC10/sin(40°)=AC10/cos (40°)=AC

ANSWER

[tex](10)sin(40 \degree) = AC[/tex]


EXPLANATION

The given triangle ABC is a right angle triangle.

Side AC of ∆ABC is opposite to the known angle which is
[tex]40 \degree[/tex]

The hypotenuse of the right angle triangle ABC is 10 in.




We use the sine ratio to arrive at the required equation.


Recall that, the sine ratio is given by
[tex] \sin( \theta) = \frac{length \: of \: opposite \: side}{length \: of \: the \: hypotenuse} [/tex]



This implies that,


[tex] \sin(40 \degree) = \frac{AC}{10} [/tex]


We now make AC the subject to obtain,


[tex]AC = (10) \sin(40 \degree) [/tex]



The correct answer is A.