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Using the quadratic formula to solve x^2=5-x what are the values of x?a. -1 +/- √21/2b.-1 +/-√19i/2c...
4 months ago
Q:
using the quadratic formula to solve x^2=5-x what are the values of x?a. -1 +/- √21/2b.-1 +/-√19i/2c.5+/- √21/2d. 1 +/- √19i/2
Accepted Solution
A:
a
you have to solve x^2+x-5=0
So x=(-1 +/- sqrt(1^2+4*1*5))/2
x=(-1 +/- sqrt(21))/2