Use the parabola tool to graph the quadratic function f(x)=2x2+32x+126 . Graph the parabola by first plotting its vertex and then plotting a second point on the parabola

[tex] f(x)=2x^2+32x+126 [/tex]Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.To find x coordinate of vertex we use formula [tex] x =\frac{-b}{2a} [/tex]From the given equation , a= 2 , b= 32, c= 126Plug in all the values [tex] x =\frac{-32}{2*2} [/tex] = -8Now plug in 8 for x in f(x) [tex] f(x)=2x^2+32x+126 [/tex] [tex] f(-8)=2(-8)^2+32(-8)+126 [/tex] = -2So vertex is (-8,-2)Now we make a table to get some other points for graphing. We assume x value before and after vertex. Plug in -9 and -7 for x in f(x) and find out y . [tex] f(x)=2x^2+32x+126 [/tex] [tex] f(-9)=2(-9)^2+32(-9)+126 [/tex] = 0 [tex] f(-7)=2(-7)^2+32(-7)+126 [/tex] = 0x ------> y-9 ------> 0-8 -------> -2-7 --------> 0Now we graph all the points.Graph is attached below.