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Unit 4 midFind the Perimeter of the triangle. Round 2 decimal places.
4 months ago
Q:
Unit 4 midFind the Perimeter of the triangle. Round 2 decimal places.
Accepted Solution
A:
A (-2, 3) B(3, 0) C(-4,-3)
[tex]\text {Length of AB = } \sqrt{(-2-3)^2+ (3-0)^2} [/tex]
[tex]\text {Length of AB = } \sqrt{(-5)^2+ (3)^2} [/tex]
[tex]\text {Length of AB = } \sqrt{25 + 9} [/tex]
[tex]\text {Length of AB = } \sqrt{34} [/tex]
[tex]\text {Length of AB = } 5.83 [/tex]
[tex]\text {Length of BC = } \sqrt{(3+4)^2+ (0+3)^2}[/tex]
[tex]\text {Length of BC = } \sqrt{(7)^2+ (3)^2}[/tex]
[tex]\text {Length of BC = } \sqrt{49 + 9}[/tex]
[tex]\text {Length of BC = } \sqrt{58}[/tex]
[tex]\text {Length of BC = } 7.62[/tex]
[tex]\text {Length of AC = } \sqrt{(-2+4)^2+ (3+3)^2}[/tex]
[tex]\text {Length of AC = } \sqrt{(2)^2+ (6)^2}[/tex]
[tex]\text {Length of AC = } \sqrt{4 + 12}[/tex]
[tex]\text {Length of AC = } \sqrt{16}[/tex]
[tex]\text {Length of AC = } 4}[/tex]
Perimeter = 5.83 + 7.62 + 4 = 17.45 units