Q:

A person sees the price of a pair of pants and a shirt at $2,200 for both. If a month later there are sales in the store with 20% on the pants and 10% on the shirt and I pay $1800, how much money was saved on the shirt?

Accepted Solution

A:
ANSWER $40 Step by Step Let's break down the problem step by step: Initially, the person sees the price of a pair of pants and a shirt at $2,200 for both. Let's denote the price of the pants as "P" and the price of the shirt as "S." So, we have: P + S = $2,200 A month later, there are sales in the store with a 20% discount on the pants and a 10% discount on the shirt. After these discounts, the person pays $1,800 for both items. 1. For the pants, there is a 20% discount, which means the person pays 80% of the original price for the pants. So, the price of the pants after the discount is: 0.80 * P 2. For the shirt, there is a 10% discount, which means the person pays 90% of the original price for the shirt. So, the price of the shirt after the discount is: 0.90 * S The total cost after the discounts is $1,800, so we have: 0.80 * P + 0.90 * S = $1,800 Now, we can set up a system of two equations with two variables: 1. P + S = $2,200 2. 0.80 * P + 0.90 * S = $1,800 We can solve this system of equations to find the values of P and S. First, let's solve Equation (1) for P: P = $2,200 - S Now, substitute this expression for P into Equation (2): 0.80 * ($2,200 - S) + 0.90 * S = $1,800 Now, solve for S: 0.80 * $2,200 - 0.80 * S + 0.90 * S = $1,800 0.80 * $2,200 + 0.10 * S = $1,800 Now, subtract 0.80 * $2,200 from both sides: 0.10 * S = $1,800 - 0.80 * $2,200 0.10 * S = $1,800 - $1,760 0.10 * S = $40 Now, divide both sides by 0.10 to find the price of the shirt (S): S = $40 / 0.10 S = $400 So, the original price of the shirt was $400. Now, to find how much money was saved on the shirt, we need to calculate the discount amount: Original price of the shirt - Price of the shirt after discount = Savings on the shirt $400 - 0.90 * $400 = $400 - $360 = $40 The person saved $40 on the shirt.