TotCo is developing a new deluxe baby bassinet. If the length of a newborn baby is normally distributed with a mean of 50 cm and a standard deviation of 5 cm, what should be the interior length of the bassinet to ensure that 99 percent of newborn babies will fit, with a safety margin of 15 cm on each end of the bassinet?

Answer:The interior length of the bassinet to ensure that 99 percent of newborn babies will fit   = 1.7 cmStep-by-step explanation:Explanation:-step(i):-Given mean of population = 50 cm   standard deviation of Population = 5 cmGiven Margin of error = 10 cmThe Margin of error is determined by [tex]M.E = \frac{Z_{\alpha } S.D}{\sqrt{n} }[/tex]Step(ii):-Given level of significance ∝ = 99 % or 1 %Z₀.₀₁ = 2.576[tex]10 = \frac{2.576 X 5}{\sqrt{n} }[/tex][tex]\sqrt{n} = \frac{2.576 X 5}{10}[/tex]√n = 1.3 squaring on both sides , we getn = 1.69≅ 1.7 cm Final answer:-The interior length of the bassinet to ensure that 99 percent of newborn babies will fit   = 1.7 cm