The weights, in pounds, of a group of student are as follows: 173 123 171 175 188 120 177 160 151 169 162 128 145 140 158 132 202 162 154 180 164 166 157 171 175 Determine the mean, standard deviation, and five-number summary for the data. a. Mean is 160.12; Standard deviation is 19.8. Five-number summary: min = 120, 4072-02-01-06-00_files/i0290000.jpg= 148, median = 162, 4072-02-01-06-00_files/i0290001.jpg= 174, max = 202 b. Mean is 162; Standard deviation is 19.8. Five-number summary: min = 120, 4072-02-01-06-00_files/i0290002.jpg= 148, median = 160.12, 4072-02-01-06-00_files/i0290003.jpg= 174, max = 202 c. Mean is 160.12; Standard deviation is 15.5. Five-number summary: min = 202, 4072-02-01-06-00_files/i0290004.jpg= 148, median = 160.12, 4072-02-01-06-00_files/i0290005.jpg= 174, max = 120 d. Mean is 162; Standard deviation is 15.5. Five-number summary: min = 202, 4072-02-01-06-00_files/i0290006.jpg= 148, median = 162, 4072-02-01-06-00_files/i0290007.jpg= 174, max = 120
Standard deviation is found by calculating the mean (160.12) , and then subtracting the mean and square root result for each number. Finally, working out the mean of the squared differences and taking the square root of the final answer results in a standard deviation of 19.76. (The attached image has the formula for finding standard deviation).
Median is the number that is found in the middle when placing the numbers in order from least to greatest.
The maximum is the largest number in the data set.
The minimum is the smallest number in the data set.