The inclination (tilt) of an amusement park ride is accelerating at a rate of 2160 degrees/min^2. What is the ride's acceleration in degrees/s^2?

[tex]\bf \begin{array}{llll} minutes&seconds\\ ------&------\\ 1m&60s\\\\ (1m)^2&(60s)^2\\ m^2&3600s^2\\\\ (1m)^3&(60s)^3\\ m^3&216000s^3 \end{array}\\\\ -------------------------------\\\\ \cfrac{2160^o}{\underline{m^2}}\cdot \cfrac{\underline{m^2}}{3600~s^2}\implies \cfrac{2160^o}{3600~s^2}\implies \cfrac{3^o}{5~s^2}\implies 0.6\frac{deg}{s^2}[/tex]