The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the perimeter to the nearest tenth of a foot and the area to the nearest square foot. Both have the diameter 20
Accepted Solution
A:
the complete question in the attached figure
we know that [area of a circle]=pi*r² [length of the circumference]=2*pi*r
Part A) (2 half circles=1 whoole circle) radius r=20/2----> r=10 ft [area 2 half circles]=pi*r²----> pi*10²----> 314.16 ft²
[perimeter 2 half circles]=2*pi*r-----> 2*pi*10----> 62.83 ft
Part B) 1/4 big circle diameter=40 ft radius=20 ft [area 1/4 big circle]=pi*r²/4-----> pi*20²/4---> 314.16 ft² [perimeter of 1/4 big circle]=2*pi*r/4-----> pi*20/2----> 31.42 ft
[area of the fountain]=314.16+314.16-----> 628.32 ft²------> 628 ft² [perimeter of the fountain]=62.83+31.42-----> 94.25 ft -------> 94.3 ft