Q:

The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the perimeter to the nearest tenth of a foot and the area to the nearest square foot. Both have the diameter 20

Accepted Solution

A:
the complete question in the attached figure

we know that
[area of a circle]=pi*r²
[length of the circumference]=2*pi*r

Part A) 
(2 half circles=1 whoole circle)
radius r=20/2----> r=10 ft
[area 2 half circles]=pi*r²----> pi*10²----> 314.16 ft²

[perimeter 2 half circles]=2*pi*r-----> 2*pi*10----> 62.83 ft

Part B)  1/4 big circle
diameter=40 ft
radius=20 ft
[area 1/4 big circle]=pi*r²/4-----> pi*20²/4---> 314.16 ft²
[perimeter of 1/4 big circle]=2*pi*r/4-----> pi*20/2----> 31.42 ft

[area of the fountain]=314.16+314.16-----> 628.32 ft²------> 628 ft²
[perimeter  of the fountain]=62.83+31.42-----> 94.25 ft  -------> 94.3 ft