Q:

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1464 and a standard deviation of 308. The local college includes a minimum score of 1680 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement? P(X > 1680) = % Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Accepted Solution

A:
Formula for z-score = (x-u)/sigma . Putting values. to get P(X>1680)
$z=\frac{1680-1464}{308}\begin{matrix} \\ =\end{matrix}0.701\to P\left(X>1680\right)=1-0.758=0.242=24.2\left(InPercentage\right)$