the abc bowling club has found that 45% of its members attended school in the pretoria area .a sample of 135 members is randomly selected from the area .assuming a normal distribution,determine the standard error for this sample
Accepted Solution
A:
Standard Error (SE) = √(p * (1 - p) / n)
Given: p = 0.45 (proportion) n = 135 (sample size)
Calculating: SE = √(0.45 * (1 - 0.45) / 135)
SE = √(0.2475 / 135)
SE = √0.001833...
SE ≈ 0.04284So,
the standard error for this sample is approximately 0.04284.