Q:

Student tickets for the football game cost $12 each. An adult ticket costs $20. $1720 was collected for the 120 tickets sold at the last game. Which system of equations can be used to solve for the number of each kind of ticket sold?A) x + y = 120; x + 20y = 1720 B) x + y = 120; 12x + 20y = 1720 C) x - y = 120; 12x + 20y = 1720 D) x + y = 1720; 12x - 20y = 120PLS HELP WILL GIVE BRANLIEST

Accepted Solution

A:
The answer is B. x + y = 120; 12x + 20y = 1720