Solve the triangle.A = 48, a = 32, b = 27I am completely blanking on how to do this, so if you could please do a step by step process, that would be greatly appreciated :)
Accepted Solution
A:
32/sin 48 = 27/sin B or sin B = (27/32)*sin 48 = 0.6270 or B = 39°; C=180-48-39 = 93° c^2 = a^2 +b^2 -2abcos C = 32^2 +27^2 -{2*32*27*cos 93}=1843 or c =43