please help i have 2 questions thank you very much.

Hello!

Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards

15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333

Multiply these to find the volume

5 * 5 * 0.08333 = 2.08325

Multiply this by the cost

2.08325 * 46 = 95.83

The answer is C) $95.83
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Question 2

You have to find the volume of the first pyramid

The equation we use is [tex] V = \frac{lwh}{3} [/tex]

V is volume
l is length
w is width
h is height

Put in the values we know

[tex]V = \frac{16 * 16 * 28}{3} [/tex]

Multiply

[tex]V = \frac{7168}{3} [/tex]

Divide

V = 2389.3333

Now we use this to find the side length of the second pyramid

[tex]2389.333 = \frac{lw * 112}{3} [/tex]

Multiply both sides by 3

7167.999 = lw * 112

Divide both sides by 112

63.9999 = lw

Since it is a square pyramid we know that sides are equal

63.999 = l^2

Take the square root of both sides

8 = l

The answer is B) 8in

Hope this helps!