4 months ago
Q:

Please assist me with these math problems asap. Round answers to the nearest tenth​

Accepted Solution

A:
Answer:8) [tex]\displaystyle 9,4 β‰ˆ hypotenuse \\ 4,9 β‰ˆ leg[/tex]6) [tex]\displaystyle 5,2 β‰ˆ horizontal\:leg \\ 4,7 β‰ˆ reflexive, vertical\:leg[/tex]5) [tex]\displaystyle 3,2 β‰ˆ reflexive, vertical\:leg[/tex]Step-by-step explanation:Obviously, use the Pythagorean Theorem for all of them:8) [tex]\displaystyle -5^2 + 7^2 = c^2 β†’ -25 + 49 = c^2 β†’ \sqrt{24} = \sqrt{c^2} β†’ 2\sqrt{6} = c β†’ 4,898979486 β‰ˆ 4,9 β‰ˆ c \\ \\ 5^2 + 8^2 = c^2 β†’ 25 + 64 = c^2 β†’ \sqrt{89} = c^2 β†’ 9,433981132 β‰ˆ c[/tex]6) [tex]\displaystyle -5,2^2 + 7^2 = c^2 β†’ -27,04 + 49 = c^2 β†’ \sqrt{21,96} = \sqrt{c^2} β†’ \frac{3\sqrt{61}}{5} = c β†’ 4,686149806 β‰ˆ 4,7 β‰ˆ c[/tex]5) [tex]\displaystyle -3,8^2 + 5^2 = c^2 β†’ -11,44 + 25 = c^2 β†’ \sqrt{10,56} = \sqrt{c^2} β†’ \frac{2\sqrt{66}}{5} = c β†’ 3,249615362 β‰ˆ 3,2[/tex]Split the isosceles base in half to get two identical legs of 3,8.I am joyous to assist you anytime.