One number is 4 less than twice a second number. find a pair of such numbers so that their product is as small as possible.
Accepted Solution
A:
For this case, the first thing we must do is define a variable. We have then: x: unknown number. First number: 2x - 4 Second number: x The product of the numbers is: [tex] y = x (2x-4)
[/tex] Rewriting: [tex] y = 2x ^ 2-4x
[/tex] Deriving the equation we have: [tex] y '= 4x-4
[/tex] We equal zero and clear x: [tex] 4x - 4 = 0
x = 4/4
x = 1[/tex] Then, the first number is: [tex] 2x - 4 = 2 (1) - 4 = 2 - 4 = - 2
[/tex] Answer: First number: -2 Second number: 1