MATH SOLVE

10 months ago

Q:
# Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20\%20%20, percent chance of winning each game, and that Cam has a 50\%50%50, percent chance of winning each game.If Justin, Cam, and Ben were to play the board game 200200200 times, which of the following is the best prediction for the number of times that Ben would win the board game?Choose 1 answer:Choose 1 answer:A303030B454545C606060D757

Accepted Solution

A:

Answer:The correct answer is C. 60.Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:Justin percent chance of winning each game = 20%Cam percent chance of winning each game = 50%Ben percent chance of winning each game = 100 - 50 - 20 = 30%2. If Justin, Cam, and Ben were to play the board game 200 times, which of the following is the best prediction for the number of times that Ben would win the board game?Number of times Ben would win the board game = Ben percent chance of winning each game * Number of times Justin, Cam and Ben were to play the board gameReplacing with the values we have:Number of times Ben would win the board game = 30% * 200Number of times Ben would win the board game = 0.30 * 200 = 60The correct answer is C. 60.