In circle A shown below, BD with a line above is the diameter and the measure of arc CB is 54 degrees. What is the measure of angle DBC
Accepted Solution
A:
the complete question in the attached figure
we know that the triangle ACB is an isosceles triangle AC=AB----------> equals to the radius so ∡ACB=∡CBA the angle ∡CAB is equals to 54° by central angle so 180°=54°+2*∡CBA--------> ∡CBA=[180-54]/2-----> 63° ∡CBA=63° ∡DBC=∡CBA-----------> ∡DBC=63°