how many liters each of a 60% acid solution and a 80% acid solution must be used to produce 80 liters of a 75% acid solution​

Answer:20 liters of 60% acid solution and 60 liters of 80% acid solutionStep-by-step explanation:Let the amount of 60% solution needed be "x", andamount of 80% solution needed be "y"Since we are making 80 liters of total solution, we can say:x + y = 80Now, from the original problem, we can write:60% of x + 80% of y = 75% of 80Converting percentages to decimals by dividing by 100 and writing the equation algebraically, we have:0.6x + 0.8y = 0.75(80)0.6x + 0.8y = 60We can write 1st equation as:x = 80 - yNow we substitute this into 2nd equation and solve for y:0.6x + 0.8y = 600.6(80 - y) + 0.8y = 6048 - 0.6y + 0.8y = 600.2y = 12y = 12/0.2y = 60Also, x is:x = 80 - yx = 80 - 60x = 20Thus, we need20 liters of 60% acid solution and 60 liters of 80% acid solution