Given: ∆DEK, DE = EKEF −∠ bisector of ∠E m∠DEF = 44°, DK = 16 Find: KF, m∠DEK, m∠DFE

Answer:KF=8, m<DEK=88degrees, m<DFE=90 degreesStep-by-step explanation:Since we already know that DK is 16 you would just have to /2 to get KF=8 m<DEK=88degrees because we already know half of the angle because EF is a bisector. so 44*2=88m<DFE=90degrees because since EF is a bisector it split it right down the middle meaning it would be equal to 90degrees.Hope this helps! :)