From a committee consisting of 5 men and 6 women, a sub-committee is formed consisting of 4 men and 3 women. How many different subcommittees are possible?

Number of combinations of 4 men from 5  =  5

number of combinations of 3 women from 6  = 6C3 =  6*5*4 / 3*2*1 = 20

So there are 5*20 = 100 subcommittees possible.