For the points P and Q, find the distance d(P, Q).
P(5, -7), Q(3, -3)
Accepted Solution
A:
You can find the distance between two points P(x1, y1) and Q(x2, y2) using the distance formula:
d(P, Q) = β((x2 - x1)^2 + (y2 - y1)^2)
For P(5, -7) and Q(3, -3):
d(P, Q) = β((3 - 5)^2 + (-3 - (-7))^2) d(P, Q) = β((-2)^2 + (4)^2) d(P, Q) = β(4 + 16) d(P, Q) = β20
So, the distance between P(5, -7) and Q(3, -3) is β20 or approximately 4.47 units.