Q:

For the points P and Q, find the distance d(P, Q). P(5, -7), Q(3, -3)

Accepted Solution

A:
You can find the distance between two points P(x1, y1) and Q(x2, y2) using the distance formula: d(P, Q) = √((x2 - x1)^2 + (y2 - y1)^2) For P(5, -7) and Q(3, -3): d(P, Q) = √((3 - 5)^2 + (-3 - (-7))^2) d(P, Q) = √((-2)^2 + (4)^2) d(P, Q) = √(4 + 16) d(P, Q) = √20 So, the distance between P(5, -7) and Q(3, -3) is √20 or approximately 4.47 units.