Q:

Find the equation of a line that has a slope of-3/11 and passes through a point (11,6)

Accepted Solution

A:
$$y-6=-\frac{3}{11}x+3$$
$$-\frac{3}{11}x+3=y-6$$
$$-\frac{3}{11}x=y-6-3$$
$$-\frac{3}{11}x=y-9$$
$$\frac{-\frac{3}{11}x}{-\frac{3}{11}}=\frac{y-9}{-\frac{3}{11}}$$
$$x=\frac{y-9}{-\frac{3}{11}}$$
$$x=-\frac{11y}{3}+33$$