MATH SOLVE

2 months ago

Q:
# Factor Polynomials Fill in the missing factors. ITEMBANK: Move to Bottom (2x + 3) (2x + 3) (2x + 5) (2x - 3) (2x - 5) (x - 2) (x - 3) (x - 4) (x - 6)2 (x2 + 4x - 3)

Accepted Solution

A:

First [tex]\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}[/tex]

[tex]\left(2x+3\right)\left(2x+3\right)=\:\left(2x+3\right)^{1+1}=\:\left(2x+3\right)^2[/tex]

The rest cannot fit into the fancy looking formula piece. So I will type them out.

2(2x + 3)^2(2x + 5)(2x - 3)(2x - 5)(x - 2)(x - 3)(x - 4)(x - 6)(2x + 4x - 3)

[tex]Simplify\ \textgreater \ x\cdot \:2+4x-3 \ \textgreater \ \mathrm{Add\:similar\:elements:}\:2x+4x=6x [/tex]

[tex]6x-3[/tex]

Finally we get

2(2x + 3)^2(2x + 5)(2x - 3)(2x - 5)(x - 2)(x - 3)(x - 4)(x - 6)(6x - 3)

Hope this helps!

[tex]\left(2x+3\right)\left(2x+3\right)=\:\left(2x+3\right)^{1+1}=\:\left(2x+3\right)^2[/tex]

The rest cannot fit into the fancy looking formula piece. So I will type them out.

2(2x + 3)^2(2x + 5)(2x - 3)(2x - 5)(x - 2)(x - 3)(x - 4)(x - 6)(2x + 4x - 3)

[tex]Simplify\ \textgreater \ x\cdot \:2+4x-3 \ \textgreater \ \mathrm{Add\:similar\:elements:}\:2x+4x=6x [/tex]

[tex]6x-3[/tex]

Finally we get

2(2x + 3)^2(2x + 5)(2x - 3)(2x - 5)(x - 2)(x - 3)(x - 4)(x - 6)(6x - 3)

Hope this helps!