This topic is trigono reasons. A student holds a slingshot and wants to burst 2 balloons that are at an average height on opposite sides. The distance between the man and the shadow is: the first is 25 meters and the second is 37 meters. I calculated the angle of the shot of the first. stone to burst each balloon The path of the projectile in each shot the distance in which both balloons are the total angle in each balloon

To solve this problem, we can use trigonometry and break it down into steps. Let's start by calculating the angles and distances involved. First, let's find the angle of elevation for bursting the first balloon, which is 25 meters away. We'll use the tangent function: tan(θ) = (height of balloon) / (distance to balloon) tan(θ1) = (0.5 meters) / (25 meters) θ1 ≈ 1.14 degrees (rounded to two decimal places) So, the angle θ1 for bursting the first balloon is approximately 1.14 degrees. Now, let's find the angle of elevation for bursting the second balloon, which is 37 meters away: tan(θ2) = (0.5 meters) / (37 meters) θ2 ≈ 0.78 degrees (rounded to two decimal places) So, the angle θ2 for bursting the second balloon is approximately 0.78 degrees. To find the total angle in each balloon's path, you would add the angle of elevation to the angle of depression (since the balloons are on opposite sides): Total angle for the first balloon = θ1 + θ2 Total angle for the first balloon ≈ 1.14 degrees + 0.78 degrees ≈ 1.92 degrees Total angle for the second balloon = θ1 + θ2 Total angle for the second balloon ≈ 1.14 degrees + 0.78 degrees ≈ 1.92 degrees So, the total angle in each balloon's path is approximately 1.92 degrees.