Find the limit of the function f(x,y)=(x^2-y^2)/(x+y), as (x,y) tends to (2,-2)
Accepted Solution
A:
$$f(x,y)=\frac{(x^2-y^2)}{(x+y)}$$
By canceling the factor, we get:
$$f(x,y)=x-y$$
as (x,y) tends to (2,-2), then
$$f(x,y)=2-(-2)$$
By addition , the answer is
4