determine in which direction the parabola opens y=-3x^2+5x+11up downleft right
Accepted Solution
A:
we have that y=-3x²+5x+11
we know that the equation of the parabola in standard form can be expressed in one of the following two ways y=ax²+bx+c the parabola opens up if a is positive and opens down if a is negative and x=ay²+by+c the parabola opens right if a is positive and opens left if a is negative
in this problem the equation is of the form y=ax²+bx+c a=-3 so the parabola opens down
using a graph tool see the attached figure the vertex of a parabola is a maximum