Christine collected some toys for a charity. She donated 3/4 of the toys to charity A. Then she donated 1/3 of the remaining toys to charity B. After the two donations, Christine had 10 toys left. How many toys did Christine originally collect?

Christine originally collected 60 toysStep-by-step explanation:Christine collected some toys for a charity.She donated 3/4 of the toys to charity AThen she donated 1/3 of the remaining toys to charity BAfter the two donations, Christine had 10 toys leftWe need to find how many toys Christine originally collectedAssume that Christine originally collected x toys∵ Christine originally collected x toys∵ She donated 3/4 of the toys to charity A∵ [tex]\frac{3}{4}*x[/tex] = [tex]\frac{3}{4}x[/tex]∴ She donated [tex]\frac{3}{4}x[/tex] to charity A∴ The remaining = x - [tex]\frac{3}{4}x[/tex] - Change x to [tex]\frac{4}{4}x[/tex] to make same denominators∴ The remaining = [tex]\frac{4}{4}x[/tex] - [tex]\frac{3}{4}x[/tex]∴ The remaining = [tex]\frac{1}{4}x[/tex]∵ She donated 1/3 of the remaining toys to charity B∵ The remainder = [tex]\frac{1}{4}x[/tex]∵ [tex]\frac{1}{3}[/tex] × [tex]\frac{1}{4}x[/tex] = [tex]\frac{1}{12}x[/tex]∴ She donated [tex]\frac{1}{12}x[/tex] to charity B∴ The remaining = [tex]\frac{1}{4}x[/tex] - [tex]\frac{1}{12}x[/tex]- Multiply the first fraction by 3 up and down to make same   denominators∴ The remaining = [tex]\frac{3}{12}x[/tex] - [tex]\frac{1}{12}x[/tex] ∴ The remaining = [tex]\frac{2}{12}x[/tex]- Simplify it by divide up and down by 2∴ The remaining = [tex]\frac{1}{6}x[/tex]∵ Christine had 10 toys left- Equate the remaining by 10∴ [tex]\frac{1}{6}x[/tex] = 10- Multiply both sides by 6∴ x = 60Christine originally collected 60 toysLearn more:You can learn more about fraction in brainly.com/question/1648978#LearnwithBrainly