Cedric and doug each had an equal amount of money. After cedric spent $35 and doug spent $28, the ratio of cedrics money to dougs money was 2:3. How much money did each boy habe at first?

Answer:Each of them had $49 at first.Step-by-step explanation:Given:Cedric and Doug each had an equal amount of money.Let the number of money they had at first be xCedric spent = $35Doug spent = $28Cedric Money left = [tex]x-35[/tex]Doug Money left = [tex]x-28[/tex]the ratio of Cedric money to Doug money was 2:3Hence the expression can be made as;[tex]\frac{x-35}{x-28}=\frac{2}{3}[/tex]Now by cross multiplication method we get;[tex]3(x-35)=2(x-28)[/tex]Now we will use distributive property to elaborate the same;[tex]3x-105=2x-56[/tex]Combining common terms we get;[tex]3x-2x=105-56[/tex]Using Subtraction property we get;[tex]x= 49[/tex]Hence $49 they each had at first.