Can you solve this????? 8x-6y=20 and -16x+7y=30: Answer this please please!

[tex]\begin{bmatrix}8x-6y=20\\ -16x+7y=30\end{bmatrix}[/tex]

[tex]Isolate\;x\;for\;8x-6y=20 \ \textgreater \ \mathrm{Add\:}6y\mathrm{\:to\:both\:sides} [/tex]
[tex]8x-6y+6y=20+6y \ \textgreater \ \mathrm{Simplify} \ \textgreater \ 8x=20+6y [/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}8 \ \textgreater \ \frac{8x}{8}=\frac{20}{8}+\frac{6y}{8} \ \textgreater \ Simplify[/tex]

[tex]\frac{8x}{8} \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:\frac{8}{8}=1 \ \textgreater \ x[/tex]

[tex]\frac{20}{8}+\frac{6y}{8} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{20+6y}{8} \ \textgreater \ Factor[/tex]
[tex]20+6y \ \textgreater \ Rewrite \ \textgreater \ 2\cdot \:10+2\cdot \:3y \ \textgreater \ \mathrm{Factor\:out\:common\:term\:}2 [/tex]
[tex]2\left(3y+10\right) \ \textgreater \ \frac{2\left(3y+10\right)}{8} \ \textgreater \ \mathrm{Cancel\:the\:common\:factor:}\:2 \ \textgreater \ x = \frac{3y+10}{4}[/tex]

So now..
[tex]\mathrm{Subsititute\:}x=\frac{3y+10}{4} \ \textgreater \ \begin{bmatrix}-16\cdot \frac{3y+10}{4}+7y=30\end{bmatrix}[/tex]

[tex]Isolate\;y\;for\;-16\cdot \frac{3y+10}{4}+7y=30[/tex]

[tex]16\cdot \frac{3y+10}{4} \ \textgreater \ \mathrm{Multiply\:fractions}:\ \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{\left(3y+10\right)\cdot \:16}{4}[/tex]
[tex]\mathrm{Divide\:the\:numbers:}\:\frac{16}{4}=4 \ \textgreater \ 4\left(3y+10\right) \ \textgreater \ -4\left(3y+10\right)+7y=30[/tex]

[tex]Expand\;-4\left(3y+10\right)+7y \ \textgreater \ -4\left(3y+10\right)[/tex]

[tex]\mathrm{Distribute\:parentheses\:using}: \:a\left(b+c\right)=ab+ac [/tex]
[tex]Where\;a=-4,\:b=3y,\:c=10 \ \textgreater \ -4\cdot \:3y-4\cdot \:10[/tex]

[tex]-4\cdot \:3y-4\cdot \:10 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:4\cdot \:3=12 \ \textgreater \ -12y-4\cdot \:10[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:4\cdot \:10=40 \ \textgreater \ -12y-40 \ \textgreater \ -12y-40+7y[/tex]

[tex]Simplify\;-12y-40+7y \ \textgreater \ \mathrm{Group\:like\:terms} \ \textgreater \ -12y+7y-40[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:-12y+7y=-5y \ \textgreater \ -5y-40 \ \textgreater \ -5y-40 = 30[/tex]

[tex]\mathrm{Add\:}40\mathrm{\:to\:both\:sides} \ \textgreater \ -5y-40+40=30+40 \ \textgreater \ -5y=70[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}-5 \ \textgreater \ \frac{-5y}{-5}=\frac{70}{-5} \ \textgreater \ Simplify \ \textgreater \ y=-14[/tex]

[tex]\mathrm{For\:}x=\frac{3y+10}{4} \ \textgreater \ \mathrm{Subsititute\:}y=-14 \ \textgreater \ x=\frac{3\left(-14\right)+10}{4}\quad \Rightarrow \quad x=-8[/tex]

[tex]Therefore\;the\:solutions\;are\;\ \textgreater \ y=-14,\:x=-8[/tex]

Hope this helps!