Q:

bright pools is building a rectangular pool at a new house. The perimeter of the pool has to be 94 feet and the length has to be 2 feet more than twice the width. What will be the length and width of the pool?​

Accepted Solution

A:
Answer:[tex]\displaystyle 15\:feet\:wide \\ 32\:feet\:long[/tex]Step-by-step explanation:{2 + 2w = l{94 = 2w + 2l94 = 2w + 2[2 + 2w]94 = 2w + 4 + 4w94 = 4 + 6w- 4 - 4_________[tex]\displaystyle \frac{90}{6} = \frac{6w}{6}[/tex][tex]\displaystyle 15 = w[/tex][Plug this back into both equations above to get the length of 32 feet]; [tex]\displaystyle 32 = l[/tex]I am joyous to assist you anytime.