Explanation: The general form of the linear line in slope-intercept form is: y = mx + c where: m is the slope c is the y-intercept
1- getting the slope: The slope of the line can be calculated using the following formula: m = [tex] \frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
We are given the points: (3,8) representing (x₁,y₁) (2,3) representing (x₂,y₂) Substitute with the givens in the above equation to get the slope as follows: m = [tex] \frac{3-8}{2-3} [/tex] = 5
Therefore, the equation now became: y = 5x + c
2- getting the y-intercept: To get the value of the c, we will use any of the given points, substitute in the equation we got in part 1 and solve for c. I will use point (2,3) as follows: y = 5x + c 3 = 5(2) + c 3 = 10 + c c = 3 - 10 c = -7
Based on the above, the equation of the line is: y = 5x - 7