An inequality is shown below:−np − 4 ≤ 2(c − 3)Which of the following solves for n? n ≤ − the quantity 2 times c minus 2 all over p n ≤ − the quantity 2 times c minus 10 all over p n ≥ − the quantity 2 times c minus 2 all over p n ≥ − the quantity 2 times c minus 10 all over p

Answer:[tex]n\geq-[/tex] the quantity [tex]2[/tex] times c minus [tex]2[/tex] all over pStep-by-step explanation:we have[tex]-np-4\leq 2(c-3)[/tex]Adds [tex]4[/tex] both sides[tex]-np-4+4\leq 2(c-3)+4[/tex][tex]-np\leq 2c-6+4[/tex][tex]-np\leq 2c-2[/tex]Divide by [tex]p[/tex] both sides[tex]-np/p\leq (2c-2)/p[/tex][tex]-n\leq (2c-2)/p[/tex] -------> Multiply by [tex]-1[/tex][tex]n\geq -\frac{(2c-2)}{p}[/tex]