After 2 hours, there are 1,400 mL of fluids remaining in a patient’s IV. The fluids drip at a rate of 300 mL per hour. Let x be the time passed, in hours, and y be the amount of fluid left in the IV, in mL. Write a linear function that models this scenario. The slope of the line is . The y-intercept of the line is . The linear function is

Answer:[tex] y(2) = 1400[/tex]Using this condition we got:[tex]1400= -300*2 +b[/tex]And solving for b we got:[tex] b= 1400+ 600= 2000[/tex]So then our linear function is given by:[tex] y = -300x +2000[/tex]Where y is the amount of fluid left and x the number of hours ellapsing Step-by-step explanation:We want to set up a linear function like this one:[tex]y = mx+b[/tex]Where y is the amount of fluid left, m the slope and b the initial amount. From the info given we know thatm = -300. And we also have the following condition:[tex] y(2) = 1400[/tex]Using this condition we got:[tex]1400= -300*2 +b[/tex]And solving for b we got:[tex] b= 1400+ 600= 2000[/tex]So then our linear function is given by:[tex] y = -300x +2000[/tex]Where y is the amount of fluid left and x the number of hours ellapsing