4 months ago
Q:

Let a be the shorter leg of a 30 ° -60 ° -90 ° triangle. sin 60 ° =- sec 60 ° =frac cos 60 ° =- csc 60 ° =frac tan 60 ° =- cot 60 ° =frac 2. Complete the table below that summarizes the values of the trigonometric ratios of the angles 30 ° 45 ° and 60 ° Questions: 1. How did you find the values? 2. What did you discover about the values you obtained? 3. What do you think makes these angles special? Why?

Let a be the shorter leg of a 30 ° -60 ° -90 ° triangle. sin 60 ° =- sec 60 ° =frac cos 60 ° =- csc 60 ° =frac tan 60 ° =- cot 60 ° =frac 2. Complete the table below that summarizes the values of the trigonometric ratios of the angles 30 ° 45 ° and 60 ° Questions: 1. How did you find the values? 2. What did you discover about the values you obtained? 3. What do you think makes these angles special? Why?

Accepted Solution

A:
Let a be the shorter leg of a 30 ° -60 ° -90 ° triangle. sin 60 ° =- sec 60 ° =frac cos 60 ° =- csc 60 ° =frac tan 60 ° =- cot 60 ° =frac 2. Complete the table below that summarizes the values of the trigonometric ratios of the angles 30 ° 45 ° and 60 ° Questions: 1. How did you find the values? 2. What did you discover about the values you obtained? 3. What do you think makes these angles special? Why? 65105bfee4724.webp